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electricity and magnetism

發問:

A deflections of 2.8 cm was observed on a cathode ray tube when an accelerating voltage of 200V was used and a current of 3.6A flowed through the solenoid which caused a deflecting magnetic field.a) what would the dflection be if the V=200V and current in the solenoid change to 4.0A?b) what would the dflection... 顯示更多 A deflections of 2.8 cm was observed on a cathode ray tube when an accelerating voltage of 200V was used and a current of 3.6A flowed through the solenoid which caused a deflecting magnetic field. a) what would the dflection be if the V=200V and current in the solenoid change to 4.0A? b) what would the dflection be if the current in the solenoid stayed at 3.6V and V changed to 1800V?

最佳解答:

(a) If V remains at 200V, the time for deflection of each electron will remain the same and the deflecting B-field will be 10/9 times of the original value if solenoid current changes to 4.0 A. Hence, the deflecting magnetic force on each electron will also be 10/9 times before. By the equation s = ut + (1/2)at2, we can deduce that, by putting u = o (since the electrons have zero velocity in the direction of deflection initially), the deflection will be 10/9 times before if t remains the same. So new deflection will be 2.8 × (10/9) = 3.11 cm. (b) If V becomes 1800 V, 9 times the value before, again by the equation: s = ut + (1/2)at2 with u = 0 Time for deflection will be 1/3 of before since a is 9 times before and s (travelling distance) remains the same. So to speak, with the solenoid current remaining at 3.6A, i.e. the deflecting magnetic force unchanged, the new deflection will be 1/9 of the original value which is: 2.8/9 = 0.311 cm

其他解答:7638E748EED250B0

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