omckyyo的部落格

標題:

• 三國演義武將登場時間 高手請進_2
• 哪裏有輪椅借？
• 深圳邊度做水晶相簿同油畫-
• 寵物小精靈鑽石版一問---第7到第8道場
• 幾題初中三角比題目(20點)
• 屯門前往伊利沙伯醫院的乘車路線
• 中文字典一問
• 我想問硝酸鈉既化學方程式係咩--
• 唔該教下我應該點找呢條數…唔該唔好賣廣告…因為真係急架….
• 請問有冇張大千藝術家的介紹-(300字)

此文章來自奇摩知識+如有不便請留言告知

f.4 math question (log)

發問:

f.4 math question (log) 圖片參考：http://imgcld.yimg.com/8/n/HA06682592/o/20130221194050.jpg

最佳解答:

18.[log(x^3*y)-log(x^2*y)]/log√x=[log(x^3)+log(y)-log(x^2)-log(y)]/0.5*log(x)=[3log(x)-2log(x)]*2/log(x)=2*log(x)/log(x)=220.[log(x^4)+log(y^2)]/log√(x^2*y)=[4*log(x)+2*log(y)]/[log(x)+0.5*log(y)]=2[2*log(x)+log(y)]/0.5[2*log(x)+log(y)]=2/0.5=422.log(2)=a, log(3)=blog(24)=log(2^3*3)=3*log(2)+log(3)=3a+b24.log(√6)=0.5*log(2*3)=0.5*[log(2)+log(3)]=(a+b)/226.log<3>(15)=log(15)/log(3)=log(3*5)/log(3)=[log(3)+log(5)]/log(3)=1+log(10/2)/log(3)=1+[l-log(2)]/log(3)=1+(1-0.301)/0.477=1+0.699/0.477=1+1.465=2.4728.log<2>(0.4)=log(0.4)/log(2)=[log(4)-log(10)]/log(2)=[2*log(2)-1]/log(2)=(2*0.301-1)/0.301=-0.398/0.301=-1.32

其他解答:7638E7481407D16B