標題:
maths questions form 2
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最佳解答:
1. AC^2 = AB^2 + BC^2(Pyth. theorem) AC^2 = (15cm)^2 + (8cm)^2 AC = 17 cm So the perimeter of the orange region = 丌 x 17cm = 17丌 cm = 53.4 cm (corr. to 3 sig. fig.) 2a) AC^2 = AB^2 + BC^2(Pyth. theorem) x^2 = 7.5^2 + 10^2 x = 12.5 b) CD = AD = 12.5 (given) CD^2 + AD^2 = 12.5^2 + 12.5^2 = 312.5 AD^2 = 17.5^2 = 306.25 Since CD^2 + AD^2 =/= AD^2, ACD is not a right-angled triangle.
其他解答:7638E748CCC65837
maths questions form 2
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q1. in the figure, o is the centre of the circle. the rectangle ABCD is of dimensions 8cmX15cm. find the perimeter of the orange colour region.***pic: http://pichost.xzmo.com/view.php?p=20070808155953.JPGq.2 in the figure,CA =CD.(a). Find the value of x(b). determine if triangle ACD is a right-angled... 顯示更多 q1. in the figure, o is the centre of the circle. the rectangle ABCD is of dimensions 8cmX15cm. find the perimeter of the orange colour region. ***pic: http://pichost.xzmo.com/view.php?p=20070808155953.JPG q.2 in the figure,CA =CD. (a). Find the value of x (b). determine if triangle ACD is a right-angled triangle. **pic: http://pichost.xzmo.com/view.php?p=20070808160631.JPG最佳解答:
1. AC^2 = AB^2 + BC^2(Pyth. theorem) AC^2 = (15cm)^2 + (8cm)^2 AC = 17 cm So the perimeter of the orange region = 丌 x 17cm = 17丌 cm = 53.4 cm (corr. to 3 sig. fig.) 2a) AC^2 = AB^2 + BC^2(Pyth. theorem) x^2 = 7.5^2 + 10^2 x = 12.5 b) CD = AD = 12.5 (given) CD^2 + AD^2 = 12.5^2 + 12.5^2 = 312.5 AD^2 = 17.5^2 = 306.25 Since CD^2 + AD^2 =/= AD^2, ACD is not a right-angled triangle.
其他解答:7638E748CCC65837
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