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A uniform 80 cm guitar string is fixed at both ends at A and B. A fingertip is touching the string at C and plucked between A and C to produce transverse vibrations, the frequency of the fundamental note is obtained is 880 Hz. The total mass of the string is 1.5g. The distance between A and C is 20 cm.What is... 顯示更多 A uniform 80 cm guitar string is fixed at both ends at A and B. A fingertip is touching the string at C and plucked between A and C to produce transverse vibrations, the frequency of the fundamental note is obtained is 880 Hz. The total mass of the string is 1.5g. The distance between A and C is 20 cm. What is the tension of the string? Ans: 232N 求解~ 謝謝!

最佳解答:

Since AC = 20 cm = 0.2 m wavelength = 2 x 0.2 m = 0.4 m Speed of wave on string = 880 x 0.4 m/s = 352 m/s Mass per unit length of string = (1.5/1000)/0.8 kg/m = 1.875 x 10^-3 kg/m Hence, 352^2 = T/(1.875 x 10^-3) where T is the string tension T = (1.875 x 10^-3) x 352^2 N = 232 N

其他解答:FAD2A23AB937987B