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Maths Question [quick]

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The distance (d) between two planets was (1.234x 5.678)^1000 km Given: log1.234=0.0913, log5.678=0.7541 and log2.512=0.4, find the value of (d)

最佳解答:

log{ (1.234x 5.678)^1000} =1000 log(1.234x 5.678) =1000x{ log1.234 + log5.678} =1000x{ 0.0913 + 0.7541} =1000x 0.8454 =8.454 =8 + 0.4 approx. =8 + log2.512 approx. Hence, (1.234x 5.678)^1000 = 10^8 x 2.512 = 2.512 x10^8 approx. 2007-01-01 14:09:24 補充： SORRY........=1000x 0.8454=845.4=845 0.4 =845 log2.512Hence,d=(1.234x 5.678)^1000= 10^845 x 2.512= 2.512 x10^845 2007-01-01 14:11:53 補充： .....=1000x 0.8454=845.4=845 + 0.4=845 + log2.512=log ( 10^845 x 2.512)Hence,d=(1.234x 5.678)^1000= 10^845 x 2.512= 2.512 x10^845

其他解答:

d = (1.234 x 5.678)^1000 log d = 1000 log (1.234 x 5.678) log d = 1000 log 1.234 + 1000 log 5.678 log d = 91.3 + 754.1 log d = 845.4 d = 10^(845.4)7638E7481407D16B