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How to solve √(k+3)2+25 = √(8-k)2 Thanks!!

最佳解答:

√(k+3)2+25 = √(8-k)2 Case 1 : k + 3 >= 0 and 8 - k >= 0 : k+3 + 25 = 8-k k = - 10 , but - 10 + 3 = - 7 < 0 , rejected. Case 2 : k + 3 >= 0 and 8 - k <= 0 : k+3 + 25 = k-8 k have no solution. Case 3 : k + 3 <= 0 and 8 - k >= 0 : - k - 3 + 25 = 8 - k k have no solution. Case 4 : k + 3 <= 0 and 8 - k <= 0 : - k - 3 + 25 = k - 8 k = 15 , But 15 + 3 > 0 , rejected. The equation have no solution. 2010-04-24 14:54:31 補充： 001 answer is wrong , √(k+3)2+25 = √(8-k)2 √(-10+3)2+25 = √(8-(-10))2 √49 + 25 = √324 7 + 25 = 18 is wrong.

其他解答:

√(k+3)2+25 = √(8-k)2 (k+3)+25 = 8-k k+28 = 8-k 2k = -20 k = -107638E7481407D16B