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標題:

college physics

發問:

A string that passes over a pulley has a 0.331 kg mass attached to one end and a 0.605 kg mass attached to the other end. The pulley, which is a disk of radius 8.50cm, has friction in its axle.What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static... 顯示更多 A string that passes over a pulley has a 0.331 kg mass attached to one end and a 0.605 kg mass attached to the other end. The pulley, which is a disk of radius 8.50cm, has friction in its axle. What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium?

最佳解答:

Net torque acting on the pulley = (Mg - mg)r = (0.605 - 0.331)(9.8)(0.085) = 0.228242 Nm This net torque should be balanced by the frictional torque in order to have static equilibrium. So, the frictional torque = 0.228 Nm (3 sig. fig.)

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