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標題:
發問:
1)[(x-1)y-1]y-x 2)m^4+m^2+1
最佳解答:
1) [(x-1)y-1]y-x = ( x - 1 )y^2 - y - x [ Expand ] = xy^2 - y^2 - y - x = x ( y^2 - 1 ) - y ( y + 1 ) = x ( y + 1 )( y - 1 ) - y ( y + 1 ) [ By a^2 - b^2 = ( a + b )( a - b ) ] = ( y + 1 ) [ x ( y - 1 ) - y ] = ( y + 1 )( xy - x - y ) 2 ) m^4 + m^2 + 1 = m^4 + 2m^2 + 1 - m^2 = ( m^2 + 1 )^2 - m^2 [ By ( a + b )^2 = a^2 + 2ab + b^2 ] = ( m^2 + 1 + m )( m^2 + 1 - m )
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factorization發問:
1)[(x-1)y-1]y-x 2)m^4+m^2+1
最佳解答:
1) [(x-1)y-1]y-x = ( x - 1 )y^2 - y - x [ Expand ] = xy^2 - y^2 - y - x = x ( y^2 - 1 ) - y ( y + 1 ) = x ( y + 1 )( y - 1 ) - y ( y + 1 ) [ By a^2 - b^2 = ( a + b )( a - b ) ] = ( y + 1 ) [ x ( y - 1 ) - y ] = ( y + 1 )( xy - x - y ) 2 ) m^4 + m^2 + 1 = m^4 + 2m^2 + 1 - m^2 = ( m^2 + 1 )^2 - m^2 [ By ( a + b )^2 = a^2 + 2ab + b^2 ] = ( m^2 + 1 + m )( m^2 + 1 - m )
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